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Quasi-static crushing of the S-shaped square tube Abaqus

In this example we intend to simulate crushing of the S-shaped square tube in the Abaqus software

The tube is made of milled steel. the cross section of the tube is square-like and the general shape of the tube is in form of S. compressive load is applied to the top of the tube causing that to be deformed

In this picture the results obtained from the Abaqus software have been compared with experimental results

In this picture the diagram of force-displacement has been drawn

This project has been validated, which means that the results obtained from Abaqus software are similar to the results of the article. In other words, this project is based on the article

### chat_bubble_outlineReviews

• ##### Tomas(verified owner)

Very good modeling

• ##### Sikara

Very interesting results, exactly like the test sample

• ##### AMIT K SINGH

Dear Sir
Thank you for this informative tutorial.
Could you send me some technical details about the input properties of the materials?
1. The plastic strain value corresponding to 350 MPa is 0.25. How do you calculate this value from a given stress-strain graph?
2. Velocity boundary condition is 0.025m/s. How do you calculate this value?

• ##### Admin

Hello
For plastic properties, you must use the strain-stress diagram and extract the yield stress to the ultimate stress from the diagram
350 Mpa is ultimate stress
This is a quasi-static issue, so loading should be done slowly, and this slow speed is indicative of the same

• ##### AMIT K SINGH

Thank you for your valuable information.
Sir, please explain the following input information.

1. For Dynamic Explicit in Abaqus, I should consider engineering stress-strain or true stress-strain curves for data extraction?
2. Also we required plastic strain instead of true or engineering strain in the plastic module of Abaqus.
Could you please explain how strain 0.25 is considered corresponding to ultimate stress value of 350Mpa?

• ##### Admin

true stress-strain
If you look at the diagram, you will notice that the stress corresponding to the strain of 0.25 is 350 MPa